Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Appendix A - Review - A.1 Algebra Essentials - A.1 Assess Your Understanding - Page A12: 119

Answer

If $x=2$ the value of the expression is $10$. If $x=1$ the value of the expression is $0$.

Work Step by Step

The given expression is $=2x^3-3x^2+5x-4$ Substitute $x=2$. $=2(2)^3-3(2)^2+5(2)-4$ Use $2^3=8$ and $2^2=4$. $=2\cdot 8-3\cdot 4+5\cdot 2-4$ Simplify. $=16-12+10-4$ $=26-16$ $=10$. Substitute $x=1$. $=2(1)^3-3(1)^2+5(1)-4$ Use $1^3=1$ and $1^2=1$. $=2\cdot 1-3\cdot 1+5\cdot 1-4$ Simplify. $=2-3+5-4$ $=7-7$ $=0$.
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