Answer
$\sqrt{5}$.
Work Step by Step
The given expression is
$=\sqrt{x^2+y^2}$
Substitute $x=2$ and $y=-1$.
$=\sqrt{(2)^2+(-1)^2}$
Use the law of exponents $(a)^n=a^{ n}$.
$=\sqrt{2^2+1^2}$
Use $2^2=4$.
$=\sqrt{4+1}$
Simplify.
$=\sqrt{5}$.
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Appendix A - Review - A.1 Algebra Essentials - A.1 Assess Your Understanding - Page A12: 115
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