Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 8 - Radical Functions - Chapter Review Exercises - Page 670: 84

Answer

$-23+52i$

Work Step by Step

Step 1: $(6+5i)(2+7i)$ Step 2: $6(2+7i)+5i(2+7i)$ Step 3: $6(2)+6(7i)+5i(2)+5i(7i)$ Step 4: $12+42i+10i+35i^{2}$ Step 5: Since $i^{2}=−1$, the expression becomes $12+42i+10i+35(-1)$ Step 6: $12+42i+10i-35$ Step 7: $12-35+10i+42i$ Step 8: $-23+52i$
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