Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 8 - Radical Functions - Chapter Review Exercises - Page 670: 70

Answer

$x= 4.5$

Work Step by Step

Given \begin{equation} \sqrt{x+2}=\sqrt{3 x-7}. \end{equation} Start by squaring both sides to eliminate the radical sign on both sides and then solve for $x$. \begin{equation} \begin{aligned} \sqrt{x+2}&=\sqrt{3 x-7}\\ \left(\sqrt{x+2}\right)^{2} & =\left(\sqrt{3 x-7}\right)^{2} \\ x+2& =3x-7\\ 9 & = 2x \\ 4.5& =x. \end{aligned} \end{equation} Check: \begin{equation} \begin{aligned} \sqrt{4.5+2}& \stackrel{?}{=} \sqrt{3 (4.5)-7} \\ \sqrt{6.5} & = \sqrt{6.5} \quad \text { True } \\ \end{aligned} \end{equation} The solution is $x= 4.5$.
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