Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 8 - Radical Functions - Chapter Review Exercises - Page 670: 76

Answer

$4i\sqrt 2$

Work Step by Step

Step 1: $\sqrt {-32}$ Step 2: $\sqrt {-1}\times\sqrt {32}$ Step 3: $\sqrt {-1}\times\sqrt 2\times\sqrt {16}$ Step 4: As $\sqrt {-1}=i$, the expression becomes $i\times\sqrt 2\times\sqrt {16}$. Step 5: $i\times\sqrt 2\times\sqrt {16}=i\times\sqrt 2\times4$ Step 6: $i\times\sqrt 2\times4=4i\sqrt 2$
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