Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 8 - Radical Functions - Chapter Review Exercises - Page 670: 55

Answer

$\frac{\sqrt {15}}{3}$

Work Step by Step

$\frac{\sqrt {5x}}{\sqrt {3x}}=\frac{\sqrt {5}\times\sqrt x}{\sqrt {3}\times\sqrt x}=\frac{\sqrt {5}}{\sqrt {3}}=\frac{\sqrt {5}\times\sqrt 3}{\sqrt {3}\times\sqrt 3}=\frac{\sqrt {5\times3}}{\sqrt {3\times3}}=\frac{\sqrt {15}}{\sqrt {9}}=\frac{\sqrt {15}}{3}$
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