Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 8 - Radical Functions - Chapter Review Exercises - Page 670: 55


$\frac{\sqrt {15}}{3}$

Work Step by Step

$\frac{\sqrt {5x}}{\sqrt {3x}}=\frac{\sqrt {5}\times\sqrt x}{\sqrt {3}\times\sqrt x}=\frac{\sqrt {5}}{\sqrt {3}}=\frac{\sqrt {5}\times\sqrt 3}{\sqrt {3}\times\sqrt 3}=\frac{\sqrt {5\times3}}{\sqrt {3\times3}}=\frac{\sqrt {15}}{\sqrt {9}}=\frac{\sqrt {15}}{3}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.