Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 8 - Radical Functions - Chapter Review Exercises - Page 670: 54


$2\sqrt 2$

Work Step by Step

$\frac{\sqrt {24}}{\sqrt 3}=\sqrt \frac{24}{3}=\sqrt {8}=\sqrt {2\times4}=\sqrt 2\times\sqrt 4=2\sqrt 2$
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