Answer
$\frac{\sqrt {21bc}}{3c}$
Work Step by Step
First, we want to cancel out what is common in both the numerator and the denominator:
$\sqrt {\frac{7b}{3c}}$
Separate the radical:
$\frac{\sqrt {7b}}{\sqrt {3c}}$
We need to get rid of the radical by multiplying both the numerator and denominator by the radical in the denominator:
$\frac{\sqrt {7b • 3c}}{\sqrt {3c • 3c}}$
Multiply what is under the radical sign:
$\frac{\sqrt {21bc}}{\sqrt {9c^2}}$
Take the square root of the denominator:
$\frac{\sqrt {21bc}}{3c}$
