Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 8 - Radical Functions - Chapter Review Exercises - Page 670: 83



Work Step by Step

Step 1: $(3+4i)(2-7i)$ Step 2: $3(2-7i)+4i(2-7i)$ Step 3: $3(2)+3(-7i)+4i(2)+4i(-7i)$ Step 4: $6-21i+8i-28i^{2}$ Step 5: Since $i^{2}=-1$, the expression becomes $6-21i+8i-28(-1)$ Step 6: $6-21i+8i+28$ Step 7: $6+28-21i+8i$ Step 8: $34-13i$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.