Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 8 - Radical Functions - Chapter Review Exercises - Page 670: 58

Answer

$10-5\sqrt{3}$

Work Step by Step

Given \begin{equation} \frac{5}{2+\sqrt{3}}. \end{equation} Simplify by rationalizing the denominator. \begin{equation} \begin{aligned} \frac{5}{2+\sqrt{3}}&=\frac{5}{2+\sqrt{3}}\cdot \frac{\left( 2-\sqrt{3}\right) }{\left( 2-\sqrt{3}\right) }\\ & =\frac{5 \left( 2-\sqrt{3}\right)}{4-3}\\ &= 5\left( 2-\sqrt{3}\right)\\ &= 10-5\sqrt{3}. \end{aligned} \end{equation}
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