Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 8 - Radical Functions - Chapter Review Exercises - Page 670: 85



Work Step by Step

Step 1: $(2-3i)(2+3i)$ Step 2: $2(2+3i)-3i(2+3i)$ Step 3: $2(2)+2(3i)-3i(2)-3i(3i)$ Step 4: $4+6i-6i-9i^{2}$ Step 5: Since $i^{2}=−1$, the expression becomes $4+6i-6i-9(-1)$ Step 6: $4+6i-6i+9$ Step 7: $4+9+6i-6i$ Step 8: $13$
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