Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 8 - Radical Functions - Chapter Review Exercises: 85

Answer

$13$

Work Step by Step

Step 1: $(2-3i)(2+3i)$ Step 2: $2(2+3i)-3i(2+3i)$ Step 3: $2(2)+2(3i)-3i(2)-3i(3i)$ Step 4: $4+6i-6i-9i^{2}$ Step 5: Since $i^{2}=−1$, the expression becomes $4+6i-6i-9(-1)$ Step 6: $4+6i-6i+9$ Step 7: $4+9+6i-6i$ Step 8: $13$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.