Answer
$\frac{\pi}{2}\approx1.57$ seconds
Work Step by Step
Given \begin{equation}
T(L)=2 \pi \sqrt{\frac{L}{32}}.
\end{equation} Find $T(2)$ when $L= 2$. \begin{equation}
\begin{aligned}
T(2)&=2 \pi \sqrt{\frac{2}{32}}\\
& =2 \pi\cdot (0.25)\\
&=\frac{\pi}{2}\\
&\approx 1.57.
\end{aligned}
\end{equation} The period of the pendulum is about $1.57$ seconds.
