Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 8 - Radical Functions - Chapter Review Exercises: 42

Answer

$12\sqrt {3a}+7\sqrt[3] {3a}$

Work Step by Step

$4\sqrt {3a}+7\sqrt[3] {3a}+8\sqrt {3a}$ =$4\sqrt {3a}+8\sqrt {3a}+7\sqrt[3] {3a}$ =$(4+8)\sqrt {3a}+7\sqrt[3] {3a}$ =$12\sqrt {3a}+7\sqrt[3] {3a}$
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