Answer
$12\sqrt {3a}+7\sqrt[3] {3a}$
Work Step by Step
$4\sqrt {3a}+7\sqrt[3] {3a}+8\sqrt {3a}$
=$4\sqrt {3a}+8\sqrt {3a}+7\sqrt[3] {3a}$
=$(4+8)\sqrt {3a}+7\sqrt[3] {3a}$
=$12\sqrt {3a}+7\sqrt[3] {3a}$
Intermediate Algebra: Connecting Concepts through Application
by Clark, Mark; Anfinson, Cynthia
Published by
Brooks Cole
ISBN 10:
0-53449-636-9
ISBN 13:
978-0-53449-636-4
Chapter 8 - Radical Functions - Chapter Review Exercises - Page 670: 42
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