Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 8 - Radical Functions - Chapter Review Exercises - Page 670: 50

Answer

$101+36\sqrt 5$

Work Step by Step

$(9+2\sqrt 5)^{2}$ =$(9+2\sqrt 5)(9+2\sqrt 5)$ =$9(9+2\sqrt 5)+2\sqrt 5(9+2\sqrt 5)$ =$81+18\sqrt 5+18\sqrt 5+2\sqrt 5(2\sqrt 5)$ =$81+(18+18)\sqrt 5+(2^{2})(\sqrt 5\times\sqrt 5)$ =$81+36\sqrt 5+4(5)$ =$81+36\sqrt 5+20$ =$81+20+36\sqrt 5$ =$101+36\sqrt 5$
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