Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 8 - Radical Functions - Chapter Review Exercises - Page 670: 51

Answer

$-99+\sqrt 7$

Work Step by Step

$(3+5\sqrt 7)(2-3\sqrt 7)$ =$3(2-3\sqrt 7)+5\sqrt 7(2-3\sqrt 7)$ =$6-9\sqrt 7+10\sqrt 7-3\sqrt 7(5\sqrt 7)$ =$6+(-9+10)\sqrt 7-(3\times5)(\sqrt 7\times\sqrt 7)$ =$6+1\sqrt 7-15(7)$ =$6+\sqrt 7-105$ =$6-105+\sqrt 7$ =$-99+\sqrt 7$
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