Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 8 - Radical Functions - Chapter Review Exercises - Page 670: 25

Answer

$11$

Work Step by Step

$\sqrt {121}=\sqrt {11^{2}}=(11^{2})^\frac{1}{2}=11$
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