Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 8 - Radical Functions - Chapter Review Exercises - Page 670: 46


$3x\sqrt {2y}$

Work Step by Step

$\sqrt {3xy}\times\sqrt {6x}$ =$\sqrt {3xy\times6x}$ =$\sqrt {2\times9\times x^{2}\times y}$ =$\sqrt {2\times3^{2}\times x^{2}\times y}$ =$3x\sqrt {2y}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.