Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.4 - Multiplying Polynomials - Exercise Set - Page 289: 79



Work Step by Step

Using $(a+b)(c+d)=ac+ad+bc+bd$ or the FOIL Method, the expression, $ \left( \dfrac{3}{5}y-6 \right)\left( \dfrac{1}{3}y-10 \right) $, is equivalent to \begin{array}{l} \left( \dfrac{3}{5}y \right)\left( \dfrac{1}{3}y \right)+\left( \dfrac{3}{5}y \right)(-10)-6\left( \dfrac{1}{3}y \right)-6(-10) \\\\= \dfrac{1}{5}y^2-6y-2y+60 \\\\= \dfrac{1}{5}y^2-8y+60 .\end{array}
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