## Intermediate Algebra (6th Edition)

$22a^3+11a^2+2a+1$
Using $(a+b)(c+d)=ac+ad+bc+bd$ or the FOIL Method, the expression, $(11a^2+1)(2a+1)$, is equivalent to \begin{array}{l} 11a^2(2a)+11a^2(1)+1(2a)+1(1) \\\\= 22a^3+11a^2+2a+1 .\end{array}