Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.4 - Multiplying Polynomials - Exercise Set: 77

Answer

$22a^3+11a^2+2a+1$

Work Step by Step

Using $(a+b)(c+d)=ac+ad+bc+bd$ or the FOIL Method, the expression, $ (11a^2+1)(2a+1) $, is equivalent to \begin{array}{l} 11a^2(2a)+11a^2(1)+1(2a)+1(1) \\\\= 22a^3+11a^2+2a+1 .\end{array}
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