Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.4 - Multiplying Polynomials - Exercise Set: 67

Answer

$9b^2-36y^2$

Work Step by Step

Using $(a+b)(a-b)=a^2-b^2$ or the product of the sum and difference of like terms, the expression, $ (3b-6y)(3b+6y) $, is equivalent to \begin{array}{l} (3b)^2-(6y)^2 \\\\= 9b^2-36y^2 .\end{array}
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