Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.4 - Multiplying Polynomials - Exercise Set - Page 289: 74

Answer

$10x^3-7x^2-3x+2$

Work Step by Step

Using the Distributive Property, the expression, $ (5x^2-x-2)(2x-1) $, is equivalent to \begin{array}{l} 5x^2(2x)+5x^2(-1)-x(2x)-x(-1)-2(2x)-2(-1) \\\\= 10x^3-5x^2-2x^2+x-4x+2 \\\\= 10x^3-7x^2-3x+2 .\end{array}
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