Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.4 - Multiplying Polynomials - Exercise Set - Page 289: 16

Answer

$12z^2-28z+8$

Work Step by Step

Using the Distributive Property, the given expression simplifies to \begin{align*} & [2z(6z)+2z(-2)]+[-4(6z)-4(-2)] \\&= [12z^2-4z]+[-24z+8] \\&= 12z^2+(-4z-24z)+8 \\&= 12z^2-28z+8 .\end{align*}
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