# Chapter 5 - Section 5.4 - Multiplying Polynomials - Exercise Set: 65

$9x^2+6x+1$

#### Work Step by Step

Using $(a+b)^2=a^2+2ab+b^2$ or the Square of a Binomial, the expression, $(3x+1)^2$, is equivalent to \begin{array}{l} (3x)^2+2(3x)(1)+(1)^2 \\\\= 9x^2+6x+1 .\end{array}

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