Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.4 - Multiplying Polynomials - Exercise Set - Page 289: 46



Work Step by Step

Using special products, the given expression is equivalent to \begin{align*} & (z-y)(z+y)(z^2-y^2) \\\\&= (z^2-y^2)(z^2-y^2) \\\\&= (z^2-y^2)^2 \\\\&= (z^2)^2+2(z^2)(-y^2)+(-y^2)^2 \\\\&= z^4-2z^2y^2+y^4 .\end{align*}
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