Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.4 - Multiplying Polynomials - Exercise Set - Page 289: 49

Answer

$x^4-625$

Work Step by Step

Using special products, the given expression is equivalent to \begin{align*} & (x-5)(x+5)(x^2+25) \\\\&= (x^2-25)(x^2+25) \\\\&= (x^2)^2-25^2 \\\\&= x^4-625 .\end{align*}
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