Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.4 - Multiplying Polynomials - Exercise Set - Page 289: 73



Work Step by Step

Using the Distributive Property, the expression, $ (4x^2-2x+5)(3x+1) $, is equivalent to \begin{array}{l} 4x^2(3x)+4x^2(1)-2x(3x)-2x(1)+5(3x)+5(1) \\\\= 12x^3+4x^2-6x^2-2x+15x+5 \\\\= 12x^3-2x^2+13x+5 .\end{array}
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