Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.4 - Multiplying Polynomials - Exercise Set: 61

Answer

$3x^2+8x-3$

Work Step by Step

Using $(a+b)(c+d)=ac+ad+bc+bd$ or the FOIL Method, the expression, $ (3x-1)(x+3) $, is equivalent to \begin{array}{l} 3x(x)+3x(3)-1(x)-1(3) \\\\= 3x^2+9x-x-3 \\\\= 3x^2+8x-3 \end{array}
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