Answer
$9b^2-48b+64$
Work Step by Step
Using the square of a binomial, $(a+b)^2=a^2+2(a)(b)+b^2$, the given expression is equivalent to
\begin{align*}
&
[5-(3b-3)]^2
\\\\&=
5^2+2(5)(-(3b-3))+(-(3b-3))^2
\\\\&
25-10(3b-3)+(3b-3)^2
\\\\&
25-30b+30+(3b-3)^2
\\\\&
-30b+55+(3b-3)^2
\\\\&
-30b+55+(3b)^2+2(3b)(-3)+(-3)^2
\\\\&
-30b+55+9b^2-18b+9
\\\\&
9b^2+(-30b-18b)+(55+9)
\\\\&
9b^2-48b+64
.\end{align*}
