Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.4 - Multiplying Polynomials - Exercise Set - Page 289: 41



Work Step by Step

Using special products techniques, the given expression is equivalent to \begin{align*} & [(2s-3)-1][(2s-3)+1] \\\\&= (2s-3)^2-1^2 \\\\&= (2s)^2+2(2s)(-3)+(-3)^2-1 \\\\&= 4s^2-12s+9-1 \\\\&= 4s^2-12s+8 .\end{align*}
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