Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.4 - Multiplying Polynomials - Exercise Set - Page 289: 37

Answer

$9x^2-\dfrac{1}{4}$

Work Step by Step

Using the special product of the sum and difference of like terms, $(a+b)(a-b)=a^2-b^2$, the given expression is equivalent to \begin{align*} & \left( 3x+\dfrac{1}{2} \right)\left( 3x-\dfrac{1}{2} \right) \\\\& (3x)^2-\left( \dfrac{1}{2} \right)^2 \\\\& 9x^2-\dfrac{1}{4} .\end{align*}
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