## Intermediate Algebra (6th Edition)

$16x^2+8xz+z^2$
Using the square of a binomial, $(a+b)^2=a^2+2(a)(b)+b^2$, the given expression is equivalent to \begin{align*} & (4x+z)^2 \\\\& (4x)^2+2(4x)(z)+(z)^2 \\\\& 16x^2+8xz+z^2 .\end{align*}