Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.4 - Multiplying Polynomials - Exercise Set - Page 289: 50



Work Step by Step

Using special products, the given expression is equivalent to \begin{align*} & (x+3)(x-3)(x^2+9) \\\\&= (x^2-9)(x^2+9) \\\\&= (x^2)^2-9^2 \\\\&= x^4-81 .\end{align*}
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