Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.4 - Multiplying Polynomials - Exercise Set - Page 289: 25

Answer

$16x^2-\dfrac{2}{3}x-\dfrac{1}{6}$

Work Step by Step

Using the FOIL Method, $(a+b)(c+d)=ac+ad+bc+bd$, the given expression simplifies to \begin{align*} & \left( 4x+\dfrac{1}{3} \right)\left( 4x-\dfrac{1}{2} \right) \\\\&= 16x^2-2x+\dfrac{4}{3}x-\dfrac{1}{6} \\\\&= 16x^2-\dfrac{6}{3}x+\dfrac{4}{3}x-\dfrac{1}{6} \\\\&= 16x^2-\dfrac{2}{3}x-\dfrac{1}{6} .\end{align*}
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