Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.4 - Multiplying Polynomials - Exercise Set - Page 289: 69

Answer

$49x^2-9$

Work Step by Step

Using $(a+b)(a-b)=a^2-b^2$ or the product of the sum and difference of like terms, the expression, $ (7x-3)(7x+3) $, is equivalent to \begin{array}{l} (7x)^2-(3)^2 \\\\= 49x^2-9 .\end{array}
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