Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.4 - Multiplying Polynomials - Exercise Set - Page 289: 44



Work Step by Step

Using the square of a binomial, $(a+b)^2=a^2+2(a)(b)+b^2$, the given expression is equivalent to \begin{align*} & [(2a^2+4a)+1]^2 \\\\&= (2a^2+4a)^2+2(2a^2+4a)(1)+(1)^2 \\\\&= (2a^2+4a)^2+4a^2+8a+1 \\\\&= (2a^2)^2+2(2a^2)(4a)+(4a)^2+4a^2+8a+1 \\\\&= 4a^4+8a(2a^2)+16a^2+4a^2+8a+1 \\\\&= 4a^4+16a^3+16a^2+4a^2+8a+1 \\\\&= 4a^4+16a^3+20a^2+8a+1 .\end{align*}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.