## College Algebra 7th Edition

$x=\frac{2d-b}{a-2c}$
$\displaystyle \frac{ax+b}{cx+d}=2$ We cross-multiply: $ax+b=2(cx+d)$ And distribute: $ax+b=2cx+2d$ And move $x$ terms to one side: $ax-2cx=2d-b$ And factor out $x$: $(a-2c)x=2d-b$ And solve for $x$: $x=\frac{2d-b}{a-2c}$