College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter P, Prerequisites - Section P.8 - Solving Basic Equations - P.8 Exercises - Page 60: 79


$x=\frac{9..44}{302}\approx 3.13$

Work Step by Step

$3.02x+1.48=10.92\displaystyle$ We subtract 1.48: $3.02x=9.44$ And solve for $x$: $x=\frac{9..44}{302}\approx 3.13$
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