College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter P, Prerequisites - Section P.8 - Solving Basic Equations - P.8 Exercises - Page 60: 73


The solution is $x=8$.

Work Step by Step

Divide 3 to both sides of the equation to obtain: $(x-3)^2=125$ Write $125$ as $5^3$ to obtain: $(x-3)^3=5^3$ Take the cube root of both sides: $x-3=\sqrt[3]{5^3} \\x-3=5$ Add 3 to both sides of the equation: $x=5+3 \\x=8$ Thus, the solution to the given equation is $x=8$.
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