College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter P, Prerequisites - Section P.8 - Solving Basic Equations - P.8 Exercises - Page 60: 70



Work Step by Step

Subtract 8 to both sides of the equation to obtain: $(x-1)^3=-8$ Write $-8$ as $(-2)^3$ to obtain: $(x-1)^3=(-2)^3$ Take the cube root of both sides: $x-1 = \sqrt[3]{(-2)^3} \\x-1 = -2$ Add $1$ to both sides of the equation: $x=-2+1 \\x=-1$ Thus, the solution to the given equation is $-1$.
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