## College Algebra 7th Edition

$x=\frac{29}{2}$
$\displaystyle \frac{2x-7}{2x+4}=\frac{2}{3}$ We cross-multiply: $(2x-7)3=2(2x+4)$ And distribute: $6x-21=4x+8$ Combine $x$ terms: $2x=29$ And solve for $x$: $x=\frac{29}{2}$