College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter P, Prerequisites - Section P.8 - Solving Basic Equations - P.8 Exercises - Page 60: 44



Work Step by Step

$\displaystyle \frac{2x-7}{2x+4}=\frac{2}{3}$ We cross-multiply: $(2x-7)3=2(2x+4)$ And distribute: $6x-21=4x+8$ Combine $x$ terms: $2x=29$ And solve for $x$: $x=\frac{29}{2}$
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