## College Algebra 7th Edition

$x=\frac{4}{3}$
$(x-1)(x+2)=(x-2)(x-3)\displaystyle$ We distribute both sides: $x^{2}+x-2=x^{2}-5x+6$ And simplify: $x-2=-5x+6$ And combine $x$ terms: $6x=8$ And solve for $x$: $x=\frac{4}{3}$