## College Algebra 7th Edition

$x=-\frac{15}{19}$
$\displaystyle \frac{12x-5}{6x+3}=2-\frac{5}{x}$ We multiply both sides by $x(6x+3)$: $(12x-5)x=2x(6x+3)-5(6x+3)$ And distribute: $12x^{2}-5x=12x^{2}+6x-30x-15$ And simplify: $12x^{2}-5x=12x^{2}-24x-15$ And combine $x$ terms: $19x=-15$ And solve for $x$: $x=-\frac{15}{19}$