College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter P, Prerequisites - Section P.8 - Solving Basic Equations - P.8 Exercises: 48

Answer

$x=-\frac{15}{19}$

Work Step by Step

$\displaystyle \frac{12x-5}{6x+3}=2-\frac{5}{x}$ We multiply both sides by $x(6x+3)$: $(12x-5)x=2x(6x+3)-5(6x+3)$ And distribute: $12x^{2}-5x=12x^{2}+6x-30x-15$ And simplify: $12x^{2}-5x=12x^{2}-24x-15$ And combine $x$ terms: $19x=-15$ And solve for $x$: $x=-\frac{15}{19}$
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