## College Algebra 7th Edition

$\left\{-5, 5\right\}$
Add $125$ to both sides: $5x^2=125$ Divide $5$ on both sides to obtain: $x^2=25$ Take the square root of both sides: $x=\pm \sqrt{25} \\x=\pm \sqrt{5^2} \\x=\pm 5$ Thus, the solution set of the given equation is $\left\{-5, 5\right\}$.