College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter P, Prerequisites - Section P.8 - Solving Basic Equations - P.8 Exercises - Page 60: 52



Work Step by Step

$\displaystyle \frac{1}{x+3}+\frac{5}{x^{2}-9}=\frac{2}{x-3}$ We multiply both sides by $(x-3)(x+3)$: $(x-3)+5=2(x+3)$ And distribute: $x+2=2x+6$ And solve for $x$: $x=-4$
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