College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter P, Prerequisites - Section P.8 - Solving Basic Equations - P.8 Exercises - Page 60: 78


$x=\pm 216$

Work Step by Step

$6x^{2/3}-216=0$ We add 216: $6x^{2/3}=216$ And divide by 6: $x^{2/3}=36$ And solve for $x$, paying attention to the possible signs of the solution: $(x^{2/3})^{3/2}=[36]^{3/2}=[(\pm 6)^{2}]^{3/2}$ $x=(\pm 6)^{3}=\pm 216$
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