## College Algebra 7th Edition

$\left\{-2, 2\right\}$
Add 16 on both sides of the equation to obtain: $x^4=16$ Write $16$ as $2^4$ to obtain: $x^4=(2)^4$ Take the fourth root of both sides to obtain: $x = \pm \sqrt[4]{2^4} \\x = \pm 22$ Thus, the solution set of the given equation is $\left\{-2, 2\right\}$.