College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter P, Prerequisites - Section P.8 - Solving Basic Equations - P.8 Exercises - Page 60: 93


$r = \sqrt{\dfrac{3V}{\pi{h}}}$

Work Step by Step

Multiply $3$ to both sides to obtain: $3V=\pi{r^2h}$ Divide $\pi{h}$ to both sides to obtain: $\dfrac{3V}{\pi{h}}=r^2$ Take the square root of both sides to obtain: $\pm\sqrt{\dfrac{3V}{\pi{h}}}=r$ The $r$ in this formula/equation is radius. A radius is a length therefore it cannot be negative. Thus, $r = \sqrt{\dfrac{3V}{\pi{h}}}$
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