College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter P, Prerequisites - Section P.8 - Solving Basic Equations - P.8 Exercises - Page 60: 66



Work Step by Step

Subtract 32 on both sides of the equation to obtain: $x^5=-32$ Write $-32$ as $(-2)^5$ to obtain: $x^5=(-2)^5$ Take the fifth root of both sides to obtain: $x = \sqrt[5]{(-2)^5} \\x = -2$ Thus, the solution set of the given equation is $\left\{-2\right\}$.
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