College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter P, Prerequisites - Section P.8 - Solving Basic Equations - P.8 Exercises - Page 60: 53


No solution.

Work Step by Step

$\displaystyle \frac{3}{x+4}=\frac{1}{x}+\frac{6x+12}{x^{2}+4x}$ We multiply both sides by $x(x+4)$: $3(x)=(x+4)+6x+12$ Then we distribute: $3x=7x+16$ And combine $x$ terms: $-4x=16$ And solve for $x$: However, if we use $x=-4$ in the original equation, we get division by 0, which is undefined. Therefore there is no solution.
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