## College Algebra 7th Edition

$\displaystyle \frac{3}{x+4}=\frac{1}{x}+\frac{6x+12}{x^{2}+4x}$ We multiply both sides by $x(x+4)$: $3(x)=(x+4)+6x+12$ Then we distribute: $3x=7x+16$ And combine $x$ terms: $-4x=16$ And solve for $x$: However, if we use $x=-4$ in the original equation, we get division by 0, which is undefined. Therefore there is no solution.