## College Algebra 7th Edition

$x=\frac{-a+1}{a^{2}-a-1}$
$a^{2}x+(a-1)=(a+1)x$ We move $x$ terms to one side: $a^{2}x-(a+1)x=-(a-1)$ Then we factor out $x$: $(a^{2}-(a+1))x=-a+1$ And simplify: $(a^{2}-a-1)x=-a+1$ Finally, we solve for $x$: $x=\frac{-a+1}{a^{2}-a-1}$